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If the reaction is slow then the exact temperature rise can be difficult to obtain as cooling occurs simultaneously with the reaction to counteract this we take readings at regular time intervals and extrapolate the temperature curve/line back to the time the reactants were added together. Study with quizlet and memorise flashcards containing terms like method of practical, why do we take regualar time intervals and extrapolate data back to the time reactants were added together, why do we take temp of reactants few mintues before they are added together and others. Assuming that all heat transfer occurs between the copper and the water, calculate the final temperature The final temperature (reached by both copper and water) is 38.8 °c This method can also be used to determine other quantities, such as the specific heat of an unknown metal. You can compensate for the heat loss by extrapolating the cooling part of the graph back to the time of mixing to give a better estimate of what the maximum temperature would be in the absence of any heat loss. Why is it important to extrapolate back to the time the reactants were mixed in order to find the final temperature (t f) Here’s the best way to solve it. It compensates for the heat lost from the calorimeter so that we can estimate the final temperature if the reaction and temperature measurement were instantaneous. Time data, and find the time at which the temperature passes this t avg point You will probably have to interpolate your data Plot the data on a proper graph paper. Plot the temperature against the time, using one of the pieces of graph paper that are available Use a straight line to extrapolate your results to the time of mixing (time = 0 s).